通过 Word Ladder - LeetCode 讲解,竟然可以抽象成无向无权图,然后通过 Queue
将其串联起来,实在好精巧。
Given two words (beginWord and endWord), and a dictionary’s word list, find the length of shortest transformation sequence from beginWord to endWord, such that:
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Only one letter can be changed at a time.
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Each transformed word must exist in the word list. Note that beginWord is not a transformed word.
Note:
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Return 0 if there is no such transformation sequence.
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All words have the same length.
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All words contain only lowercase alphabetic characters.
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You may assume no duplicates in the word list.
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You may assume beginWord and endWord are non-empty and are not the same.
Example 1:
Input: beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"] Output: 5 Explanation: As one shortest transformation is "hit" -> "hot" -> "dot" -> "dog" -> "cog", return its length 5.
Example 2:
Input: beginWord = "hit" endWord = "cog" wordList = ["hot","dot","dog","lot","log"] Output: 0 Explanation: The endWord "cog" is not in wordList, therefore no possible* *transformation.
link:{sourcedir}/_0127_WordLadder.java[role=include]