06.AG08-TopEarners.sql

/*
Top Earners

We define an employee's total earnings to be their monthly  salary X month worked, and the maximum total earnings to be the maximum total earnings for any employee in the Employee table. Write a query to find the maximum total earnings for all employees as well as the total number of employees who have maximum total earnings. Then print these values as 2 space-separated integers.

Input Format

The Employee table containing employee data for a company is described as follows:
+--------------+---------+
|   Column     |  Type   |
+--------------+---------+
| employee_id  | Integer |
| name         | String  |
| months       | Integer |
| salary       | Integer |
+--------------+---------+

where employee_id is an employee's ID number, name is their name, months is the total number of months they've been working for the company, and salary is the their monthly salary.

Sample Input
+-------------+----------+---------+--------+
| employee_id |  name    | months  | salary |
+-------------+----------+---------+--------+
|       12228 | Rose     |      15 |   1968 |
|       33645 | Angela   |       1 |   3443 |
|       45692 | Frank    |      17 |   1608 |
|       56118 | Patrick  |       7 |   1345 |
|       59725 | Lisa     |      11 |   2330 |
|       74197 | Kimberly |      16 |   4372 |
|       78454 | Bonnie   |       8 |   1771 |
|       83565 | Michael  |       6 |   2017 |
|       98607 | Todd     |       5 |   3396 |
|       99989 | Joe      |       9 |   3573 |
+-------------+----------+---------+--------+

Sample Output

69952 1

Explanation

The table and earnings data is depicted in the following diagram: 
+-------------+----------+---------+---------+----------+
| employee_id |  name    | months  | salary  | earnings |
+-------------+----------+---------+---------+----------+
|       12228 | Rose     |      15 |    1968 |    29520 |
|       33645 | Angela   |       1 |    3443 |     3443 |
|       45692 | Frank    |      17 |    1608 |    27336 |
|       56118 | Patrick  |       7 |    1345 |     9415 |
|       59725 | Lisa     |      11 |    2330 |    25630 |
|       74197 | Kimberly |      16 |    4372 |    69952 |
|       78454 | Bonnie   |       8 |    1771 |    14168 |
|       83565 | Michael  |       6 |    2017 |    12102 |
|       98607 | Todd     |       5 |    3396 |    16980 |
|       99989 | Joe      |       9 |    3573 |    32157 |
+-------------+----------+---------+---------+----------+

The maximum earnings value is 69952. The only employee with earnings = 69952 is Kimberly, so we print the maximum earnings value (69952) and a count of the number of employees who have earned $69952 (which is 1) as two space-separated values
*/

use hackerrank;

GO

raiserror('Now at aggregation.proc_08topearners creation ....',0,1)

GO

CREATE or ALTER PROCEDURE aggregation.proc_08topearners
AS
select salary*months as SALARY, count(1) as EMPCOUNT from aggregation.EMPLOYEES2 group by salary*months order by salary*months desc offset 0 rows fetch next 1 rows only;
GO

raiserror('Now at AggregationTestClass.test_08topearners creation ....',0,1)

GO

CREATE or ALTER PROCEDURE AggregationTestClass.test_08topearners
AS
BEGIN
    IF OBJECT_ID('actual') IS NOT NULL DROP TABLE actual;
    IF OBJECT_ID('expected') IS NOT NULL DROP TABLE expected;

	CREATE TABLE actual (
	      SALARY     int    NOT NULL,
		  EMPCOUNT	 int	NULL
    );

    INSERT INTO actual (SALARY, EMPCOUNT) exec aggregation.proc_08topearners

    CREATE TABLE expected (
	      SALARY     int    NOT NULL,
		  EMPCOUNT	 int	NULL
    );

	INSERT INTO expected (SALARY, EMPCOUNT) SELECT 108064,7;

    EXEC tSQLt.AssertEqualsTable 'expected', 'actual';

END;

GO

--exec tSQLt.Run 'AggregationTestClass.[test_08topearners]';