Goat_Latin.py

# You are given a string sentence that consist of words separated by spaces. Each word consists of lowercase and uppercase letters only.

# We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat Latin are as follows:

# If a word begins with a vowel ('a', 'e', 'i', 'o', or 'u'), append "ma" to the end of the word.
# For example, the word "apple" becomes "applema".
# If a word begins with a consonant (i.e., not a vowel), remove the first letter and append it to the end, then add "ma".
# For example, the word "goat" becomes "oatgma".
# Add one letter 'a' to the end of each word per its word index in the sentence, starting with 1.
# For example, the first word gets "a" added to the end, the second word gets "aa" added to the end, and so on.
# Return the final sentence representing the conversion from sentence to Goat Latin.

 

# Example 1:

# Input: sentence = "I speak Goat Latin"
# Output: "Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
# Example 2:

# Input: sentence = "The quick brown fox jumped over the lazy dog"
# Output: "heTmaa uickqmaaa rownbmaaaa oxfmaaaaa umpedjmaaaaaa overmaaaaaaa hetmaaaaaaaa azylmaaaaaaaaa ogdmaaaaaaaaaa"
 

# Constraints:

# 1 <= sentence.length <= 150
# sentence consists of English letters and spaces.
# sentence has no leading or trailing spaces.
# All the words in sentence are separated by a single space.


class Solution:
    def toGoatLatin(self, sentence: str) -> str:
        # let's define the vowels
        vowels = ['a', 'e', 'i', 'o', 'u']
        
        # let's seperate the words from the sentence in a list
        words = sentence.split(' ')
        
        answer = ""
        # now we loop thrugh each word and modify it
        count_a = 1
        for i in range(len(words)):
            new_word = ""
            # check the first letter of the word
            if words[i][0].lower() in vowels:
                new_word += (words[i] + 'ma' + 'a'*count_a)
            else:
                new_word += (words[i][1:] + words[i][0] + 'ma' + 'a'*count_a)
              
            count_a += 1
            # if we reached the last word, we don't need to add a space
            if i == len(words) - 1:
                answer += new_word
                break
            answer += new_word + ' '
        
        return answer