check_if_all_characters_have_equal_number_of_occurences.py

# Given a string s, return true if s is a good string, or false otherwise.

# A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).

 

# Example 1:

# Input: s = "abacbc"
# Output: true
# Explanation: The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.
# Example 2:

# Input: s = "aaabb"
# Output: false
# Explanation: The characters that appear in s are 'a' and 'b'.
# 'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.
 

# Constraints:

# 1 <= s.length <= 1000
# s consists of lowercase English letters.

class Solution:
    def areOccurrencesEqual(self, s: str) -> bool:
        map_freq = {}
        
        for char in s:
            if char not in map_freq:
                map_freq[char] = 1
            else:
                map_freq[char] += 1
        
        assert_freq = map_freq[s[0]]
        for char, freq in map_freq.items():
            if freq != assert_freq:
                return False
        
        return True