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Copy pathfind_words_that_can_be_formed_by_characters.py
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find_words_that_can_be_formed_by_characters.py
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# You are given an array of strings words and a string chars.
# A string is good if it can be formed by characters from chars (each character can only be used once).
# Return the sum of lengths of all good strings in words.
# Example 1:
# Input: words = ["cat","bt","hat","tree"], chars = "atach"
# Output: 6
# Explanation: The strings that can be formed are "cat" and "hat" so the answer is 3 + 3 = 6.
# Example 2:
# Input: words = ["hello","world","leetcode"], chars = "welldonehoneyr"
# Output: 10
# Explanation: The strings that can be formed are "hello" and "world" so the answer is 5 + 5 = 10.
# Constraints:
# 1 <= words.length <= 1000
# 1 <= words[i].length, chars.length <= 100
# words[i] and chars consist of lowercase English letters.
class Solution:
def countCharacters(self, words: List[str], chars: str) -> int:
answer = 0
carry = False
for word in words:
temp = list(chars)
for ch in word:
if ch in temp:
index = temp.index(ch)
del temp[index]
else:
carry = True
break
if carry:
carry = False
continue
answer += len(word)
return answer