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main.cpp
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/// Source : https://leetcode.com/problems/number-of-islands/description/
/// Author : liuyubobobo
/// Time : 2017-11-18
#include <iostream>
#include <vector>
#include <cassert>
using namespace std;
/// Floodfill - DFS
/// Recursion implementation
///
/// Time Complexity: O(n*m)
/// Space Complexity: O(n*m)
class Solution {
private:
int d[4][2] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};
int m, n;
vector<vector<bool>> visited;
bool inArea(int x, int y){
return x >= 0 && x < m && y >= 0 && y < n;
}
void dfs(vector<vector<char>>& grid, int x, int y){
//assert(inArea(x,y));
visited[x][y] = true;
for(int i = 0; i < 4; i ++){
int newx = x + d[i][0];
int newy = y + d[i][1];
if(inArea(newx, newy) && !visited[newx][newy] && grid[newx][newy] == '1')
dfs(grid, newx, newy);
}
return;
}
public:
int numIslands(vector<vector<char>>& grid) {
m = grid.size();
if(m == 0)
return 0;
n = grid[0].size();
if(n == 0)
return 0;
for(int i = 0 ; i < m ; i ++)
visited.push_back(vector<bool>(n, false));
int res = 0;
for(int i = 0 ; i < m ; i ++)
for(int j = 0 ; j < n ; j ++)
if(grid[i][j] == '1' && !visited[i][j]){
dfs(grid, i, j);
res ++;
}
return res;
}
};
int main() {
char g1[4][5] = {
{'1','1','1','1','0'},
{'1','1','0','1','0'},
{'1','1','0','0','0'},
{'0','0','0','0','0'}
};
vector<vector<char>> grid1;
for(int i = 0 ; i < 4 ; i ++)
grid1.push_back( vector<char>(g1[i], g1[i] + sizeof( g1[i])/sizeof(char)));
cout << Solution().numIslands(grid1) << endl;
// 1
// ---
char g2[4][5] = {
{'1','1','0','0','0'},
{'1','1','0','0','0'},
{'0','0','1','0','0'},
{'0','0','0','1','1'}
};
vector<vector<char>> grid2;
for(int i = 0 ; i < 4 ; i ++)
grid2.push_back(vector<char>(g2[i], g2[i] + sizeof( g2[i])/sizeof(char)));
cout << Solution().numIslands(grid2) << endl;
// 2
return 0;
}