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main.cpp
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/// Source : https://leetcode.com/problems/minimum-cost-to-hire-k-workers/description/
/// Author : liuyubobobo
/// Time : 2010-06-25
#include <iostream>
#include <vector>
#include <queue>
#include <cassert>
using namespace std;
/// Greedy + Priority Queue
/// Time Complexity: O(nlogn)
/// Space Complexity: O(n)
class Worker{
private:
int q, w;
double ratio;
public:
Worker(int q, int w){
this->q = q;
this->w = w;
this->ratio = (double)w / q;
}
double getRatio() const{
return ratio;
}
int getQuality() const{
return q;
}
};
bool cmpWorkers (const Worker& w1, const Worker& w2){
return w1.getRatio() < w2.getRatio();
}
class Solution {
public:
double mincostToHireWorkers(vector<int>& quality, vector<int>& wage, int K) {
assert(K <= quality.size());
vector<Worker> workers;
for(int i = 0 ; i < quality.size() ; i ++)
workers.push_back(Worker(quality[i], wage[i]));
sort(workers.begin(), workers.end(), cmpWorkers);
priority_queue<int> pq;
int sumq = 0;
for(int i = 0 ; i < K ; i ++){
pq.push(workers[i].getQuality());
sumq += workers[i].getQuality();
}
double res = sumq * workers[K-1].getRatio();
for(int i = K ; i < workers.size() ; i ++){
int maxq = pq.top();
pq.pop();
sumq -= maxq;
pq.push(workers[i].getQuality());
sumq += workers[i].getQuality();
res = min(res, sumq * workers[i].getRatio());
}
return res;
}
};
int main() {
vector<int> quality1 = {10, 20, 5};
vector<int> wage1 = {70, 50, 30};
int K1 = 2;
cout << Solution().mincostToHireWorkers(quality1, wage1, K1) << endl;
// 105.00000
vector<int> quality2 = {3, 1, 10, 10, 1};
vector<int> wage2 = {4, 8, 2, 2, 7};
int K2 = 3;
cout << Solution().mincostToHireWorkers(quality2, wage2, K2) << endl;
// 30.66667
return 0;
}