Skip to content

Latest commit

 

History

History
155 lines (109 loc) · 5.47 KB

File metadata and controls

155 lines (109 loc) · 5.47 KB
comments difficulty edit_url rating source tags
true
Hard
2411
Weekly Contest 421 Q4
Hash Table
Math
String
Dynamic Programming
Counting

中文文档

Description

You are given a string s consisting of lowercase English letters, an integer t representing the number of transformations to perform, and an array nums of size 26. In one transformation, every character in s is replaced according to the following rules:

  • Replace s[i] with the next nums[s[i] - 'a'] consecutive characters in the alphabet. For example, if s[i] = 'a' and nums[0] = 3, the character 'a' transforms into the next 3 consecutive characters ahead of it, which results in "bcd".
  • The transformation wraps around the alphabet if it exceeds 'z'. For example, if s[i] = 'y' and nums[24] = 3, the character 'y' transforms into the next 3 consecutive characters ahead of it, which results in "zab".

Return the length of the resulting string after exactly t transformations.

Since the answer may be very large, return it modulo 109 + 7.

 

Example 1:

Input: s = "abcyy", t = 2, nums = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2]

Output: 7

Explanation:

  • First Transformation (t = 1):

    <ul>
    	<li><code>&#39;a&#39;</code> becomes <code>&#39;b&#39;</code> as <code>nums[0] == 1</code></li>
    	<li><code>&#39;b&#39;</code> becomes <code>&#39;c&#39;</code> as <code>nums[1] == 1</code></li>
    	<li><code>&#39;c&#39;</code> becomes <code>&#39;d&#39;</code> as <code>nums[2] == 1</code></li>
    	<li><code>&#39;y&#39;</code> becomes <code>&#39;z&#39;</code> as <code>nums[24] == 1</code></li>
    	<li><code>&#39;y&#39;</code> becomes <code>&#39;z&#39;</code> as <code>nums[24] == 1</code></li>
    	<li>String after the first transformation: <code>&quot;bcdzz&quot;</code></li>
    </ul>
    </li>
    <li>
    <p><strong>Second Transformation (t = 2):</strong></p>
    
    <ul>
    	<li><code>&#39;b&#39;</code> becomes <code>&#39;c&#39;</code> as <code>nums[1] == 1</code></li>
    	<li><code>&#39;c&#39;</code> becomes <code>&#39;d&#39;</code> as <code>nums[2] == 1</code></li>
    	<li><code>&#39;d&#39;</code> becomes <code>&#39;e&#39;</code> as <code>nums[3] == 1</code></li>
    	<li><code>&#39;z&#39;</code> becomes <code>&#39;ab&#39;</code> as <code>nums[25] == 2</code></li>
    	<li><code>&#39;z&#39;</code> becomes <code>&#39;ab&#39;</code> as <code>nums[25] == 2</code></li>
    	<li>String after the second transformation: <code>&quot;cdeabab&quot;</code></li>
    </ul>
    </li>
    <li>
    <p><strong>Final Length of the string:</strong> The string is <code>&quot;cdeabab&quot;</code>, which has 7 characters.</p>
    </li>
    

Example 2:

Input: s = "azbk", t = 1, nums = [2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2]

Output: 8

Explanation:

  • First Transformation (t = 1):

    <ul>
    	<li><code>&#39;a&#39;</code> becomes <code>&#39;bc&#39;</code> as <code>nums[0] == 2</code></li>
    	<li><code>&#39;z&#39;</code> becomes <code>&#39;ab&#39;</code> as <code>nums[25] == 2</code></li>
    	<li><code>&#39;b&#39;</code> becomes <code>&#39;cd&#39;</code> as <code>nums[1] == 2</code></li>
    	<li><code>&#39;k&#39;</code> becomes <code>&#39;lm&#39;</code> as <code>nums[10] == 2</code></li>
    	<li>String after the first transformation: <code>&quot;bcabcdlm&quot;</code></li>
    </ul>
    </li>
    <li>
    <p><strong>Final Length of the string:</strong> The string is <code>&quot;bcabcdlm&quot;</code>, which has 8 characters.</p>
    </li>
    

 

Constraints:

  • 1 <= s.length <= 105
  • s consists only of lowercase English letters.
  • 1 <= t <= 109
  • nums.length == 26
  • 1 <= nums[i] <= 25

Solutions

Solution 1

Python3

Java

C++

Go