可以将多个dispatch 合并成一个操作

[whxcode]

我刚刚学react，看见您写的小书对我帮助很大。感谢
function createStore(s,stateChanger) {
const listeners = []
const queue = []
let state = s
const getState = () => state
let timerId :any = 0
const dispatch = (action) => {
if(typeof action == 'function') {
const d = stateChanger(state,action())
for(const value of listeners) {
value(d)
state = d
}
return;
}
queue.push(() => {
return stateChanger(state,action)
})
clearImmediate(timerId)
timerId = setImmediate (() => {
let d = null
while (queue.length) {
d = queue.shift()()
state = d
}
for(const value of listeners) {
value(d)
}
},1)
}
const subscribe = (listen) => listeners.push(listen)
return { getState,dispatch,subscribe }
}