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As mentioned in #2982, it would be nice for the newly introduced * dereference operator to implicitly lift to optional references. I.e., assuming the * operator has type fun<T: Primitive>(_ ref: &T): T, we should implicitly overload the operator to also have type fun<T: Primitive>(_ ref: &T?): T?.
Suggested Solution
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The text was updated successfully, but these errors were encountered:
Issue to be solved
As mentioned in #2982, it would be nice for the newly introduced
*
dereference operator to implicitly lift to optional references. I.e., assuming the*
operator has typefun<T: Primitive>(_ ref: &T): T
, we should implicitly overload the operator to also have typefun<T: Primitive>(_ ref: &T?): T?
.Suggested Solution
No response
The text was updated successfully, but these errors were encountered: