131. Given a string S consisting of only '(' and ')', print 'yes' if it is balanced otherwise print 'no'.

Given a string S consisting of only '(' and ')', print 'yes' if it is balanced otherwise print 'no'.
Sample Testcase :
INPUT
(())
OUTPUT
yes



s=input()
openingbraces = ['(', '[', '{']
closingbraces = [')', ']', '}']
st = []
for x in s:
  if x in openingbraces:
    st.append(x)
  if x in closingbraces:
    if len(st) > 0:
      ob = st.pop()
      #print(ob)
    else:
      print("no")
    if (x==')' and ob!='(') or (x==']' and ob!='[') or (x=='{' and ob!='}'):
      print ("no")
if len(st)==0:
  print("yes")
else:
  print("no")