Hackerrank: If-Else Question

#Task
#Given an integer,n, perform the following conditional actions:

#If n is odd, print Weird
#If n is even and in the inclusive range of  to , print Not Weird
#If n is even and in the inclusive range of  to , print Weird
#If n is even and greater than , print Not Weird
#Input Format : A single line containing a positive integer, n

#Constraints : 1<=n<=100

#!/bin/python

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(raw_input().strip())
    n = random.randint(1,100)
    if n%2 == 0:
        if n in range(2,6):
            print('Not Weird')
        elif n in range(6,21):
            print('Weird')
        elif n>20:
            print('Not Weird')
        else:
            print('Weird')
       
# 틀린 답안

if __name__ == '__main__':
    n = int(raw_input().strip())
    #n = random.randint(1,100) 랜덤값을 줘버리면 안된다. 왜냐하면 range함수를 이용하여 이미 범위내 연속된 숫자를 주기 때문이다.
    if n in range (6, 21) or n % 2 != 0: #odd number 홀수일 때는 n%2!=0 짝 even number 짝수일 때 n%2==0
        print("Weird")
    else:
        print("Not Weird")
        
 # 맞는 답안