53_01_NumberOfK.py

# -*- coding: utf-8 -*-
# @File    : 53_01_NumberOfK.py
# @Date    : 2021-06-20
# @Author  : tc
"""
剑指 Offer 53 - I. 在排序数组中查找数字 I
统计一个数字在排序数组中出现的次数。

示例 1:

输入: nums = [5,7,7,8,8,10], target = 8
输出: 2
示例 2:

输入: nums = [5,7,7,8,8,10], target = 6
输出: 0

二分法

参考：https://leetcode-cn.com/problems/zai-pai-xu-shu-zu-zhong-cha-zhao-shu-zi-lcof/solution/mian-shi-ti-53-i-zai-pai-xu-shu-zu-zhong-cha-zha-5/

"""
class Solution:
    def search(self, nums: [int], target: int) -> int:
        # 搜索右边界 right
        i, j = 0, len(nums) - 1
        while i <= j:
            m = (i + j) // 2
            if nums[m] <= target: i = m + 1
            else: j = m - 1
        right = i
        # 若数组中无 target ，则提前返回
        if j >= 0 and nums[j] != target: return 0
        # 搜索左边界 left
        i = 0
        while i <= j:
            m = (i + j) // 2
            if nums[m] < target: i = m + 1
            else: j = m - 1
        left = j
        return right - left - 1