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Une correction.
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Skyost authored Jun 12, 2024
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Soit $(X, \mathcal{A}, \mu)$ un espace mesuré de mesure finie.

\begin{notation}
On note $\forall p \in [1, 2]$, $L_p = L_p(X, \mathcal{A}, \mu)$.
On note $\forall p \in ]1, 2[$, $L_p = L_p(X, \mathcal{A}, \mu)$.
\end{notation}

\begin{lemma}
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