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First completed : July 04, 2024
Last updated : July 04, 2024
Related Topics : Dynamic Programming, Tree, Depth-First Search, Binary Tree
Acceptance Rate : 40.5 %
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def maxPathSum(self, root: Optional[TreeNode]) -> int:
# Schema: (longest independent, longestChain)
def helper(curr: Optional[TreeNode]) -> Tuple[int, int] :
if not curr :
return (None, None)
if not curr.left and not curr.right :
return (curr.val, curr.val)
leftInd, leftChn = helper(curr.left)
rightInd, rightChn = helper(curr.right)
independentCandidates = [curr.val]
chainCandidates = [0]
if leftInd != None :
independentCandidates.append(leftInd)
independentCandidates[0] += max(0, leftChn)
chainCandidates.append(leftChn)
if rightInd != None :
independentCandidates.append(rightInd)
independentCandidates[0] += max(0, rightChn)
chainCandidates.append(rightChn)
return (max(independentCandidates), max(chainCandidates) + curr.val)
return max(helper(root))