_3136. Valid Word.md

3136. Valid Word

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First completed : July 03, 2024

Last updated : July 03, 2024

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Related Topics : String

Acceptance Rate : 38.22 %

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Solutions

• e3136.c
• e3136.py

C

e3136.c

bool isValid(char* word) {
    bool cons = false;
    bool vow = false;
    int len = 0;

    while (*word) {
        len++;
        if (*word >= 65 && *word <= 90) {
            *word += 32;
        }

        // letter
        if (*word >= 97 && *word <= 122) {
            switch (*word) {
                case 'a' :
                case 'e' :
                case 'i' :
                case 'o' :
                case 'u' :
                    vow = true;
                    break;
                default :
                    cons = true;
                    break;
            }
            word++;
            continue;
        }

        if (*word >= 48 && *word <= 57) {
            word++;
            continue;
        }

        return false;
    }

    return cons && vow && (len >= 3);
}

Python

e3136.py

class Solution:
    def isValid(self, word: str) -> bool:
        if not word.isalnum() :
            return False

        if len(word) < 3 :
            return False

        cons, vow = False, False
        vowels = set('aeiou')

        for i, c in enumerate(word) :
            if c.lower() in vowels :
                vow = True
            elif not c.isnumeric() :
                cons = True
            
            if vow and cons :
                return True
        return False