[Bronze I] Title: 이항 계수 1, Time: 36 ms, Memory: 32412 KB -BaekjoonHub

백준/Bronze/11050. 이항 계수 1/README.md

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+# [Bronze I] 이항 계수 1 - 11050 
+
+[문제 링크](https://www.acmicpc.net/problem/11050) 
+
+### 성능 요약
+
+메모리: 32412 KB, 시간: 36 ms
+
+### 분류
+
+조합론, 구현, 수학
+
+### 제출 일자
+
+2025년 1월 6일 21:52:46
+
+### 문제 설명
+
+<p>자연수 <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(N\)</span></mjx-container>과 정수 <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D43E TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>K</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(K\)</span></mjx-container>가 주어졌을 때 이항 계수 <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mrow><mjx-texatom texclass="OPEN"><mjx-mo class="mjx-sop"><mjx-c class="mjx-c28 TEX-S1"></mjx-c></mjx-mo></mjx-texatom><mjx-mfrac><mjx-frac atop="true" delims="true" style="vertical-align: -0.345em;"><mjx-num style="padding-bottom: 0.306em;"><mjx-mi class="mjx-i" size="s"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-num><mjx-den><mjx-mi class="mjx-i" size="s"><mjx-c class="mjx-c1D43E TEX-I"></mjx-c></mjx-mi></mjx-den></mjx-frac></mjx-mfrac><mjx-texatom texclass="CLOSE"><mjx-mo class="mjx-sop"><mjx-c class="mjx-c29 TEX-S1"></mjx-c></mjx-mo></mjx-texatom></mjx-mrow></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow data-mjx-texclass="ORD"><mrow data-mjx-texclass="OPEN"><mo minsize="1.2em" maxsize="1.2em">(</mo></mrow><mfrac linethickness="0"><mi>N</mi><mi>K</mi></mfrac><mrow data-mjx-texclass="CLOSE"><mo minsize="1.2em" maxsize="1.2em">)</mo></mrow></mrow></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(\binom{N}{K}\)</span></mjx-container>를 구하는 프로그램을 작성하시오.</p>
+
+### 입력 
+
+ <p>첫째 줄에 <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(N\)</span></mjx-container>과 <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D43E TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>K</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(K\)</span></mjx-container>가 주어진다. (1 ≤ <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(N\)</span></mjx-container> ≤ 10, 0 ≤ <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D43E TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>K</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(K\)</span></mjx-container> ≤ <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mi class="mjx-i"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(N\)</span></mjx-container>)</p>
+
+### 출력 
+
+ <p> <mjx-container class="MathJax" jax="CHTML" style="font-size: 109%; position: relative;"><mjx-math class="MJX-TEX" aria-hidden="true"><mjx-mrow><mjx-texatom texclass="OPEN"><mjx-mo class="mjx-sop"><mjx-c class="mjx-c28 TEX-S1"></mjx-c></mjx-mo></mjx-texatom><mjx-mfrac><mjx-frac atop="true" delims="true" style="vertical-align: -0.345em;"><mjx-num style="padding-bottom: 0.306em;"><mjx-mi class="mjx-i" size="s"><mjx-c class="mjx-c1D441 TEX-I"></mjx-c></mjx-mi></mjx-num><mjx-den><mjx-mi class="mjx-i" size="s"><mjx-c class="mjx-c1D43E TEX-I"></mjx-c></mjx-mi></mjx-den></mjx-frac></mjx-mfrac><mjx-texatom texclass="CLOSE"><mjx-mo class="mjx-sop"><mjx-c class="mjx-c29 TEX-S1"></mjx-c></mjx-mo></mjx-texatom></mjx-mrow></mjx-math><mjx-assistive-mml unselectable="on" display="inline"><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow data-mjx-texclass="ORD"><mrow data-mjx-texclass="OPEN"><mo minsize="1.2em" maxsize="1.2em">(</mo></mrow><mfrac linethickness="0"><mi>N</mi><mi>K</mi></mfrac><mrow data-mjx-texclass="CLOSE"><mo minsize="1.2em" maxsize="1.2em">)</mo></mrow></mrow></math></mjx-assistive-mml><span aria-hidden="true" class="no-mathjax mjx-copytext">\(\binom{N}{K}\)</span></mjx-container>를 출력한다.</p>
+

백준/Bronze/11050. 이항 계수 1/이항 계수 1.py

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+import sys
+input = sys.stdin.readline
+
+N, K = map(int, input().split())
+
+result = 1
+for i in range(K):
+    result *= N
+    N -= 1
+
+divisor = 1
+for i in range(2, K+1):
+    divisor *= i
+
+print(result // divisor)