Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

assignemnt 4 fangqi liu #212

Open
wants to merge 1 commit into
base: master
Choose a base branch
from
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
103 changes: 88 additions & 15 deletions Assignment 4.Rmd
Original file line number Diff line number Diff line change
@@ -1,5 +1,5 @@
---
title: "Assignment 4: K Means Clustering"
title: 'Assignment 4: K Means Clustering'
---

In this assignment we will be applying the K-means clustering algorithm we looked at in class. At the following link you can find a description of K-means:
Expand All @@ -8,13 +8,15 @@ https://www.cs.uic.edu/~wilkinson/Applets/cluster.html


```{r}
library()
library(dplyr)
library(tidyr)

```

Now, upload the file "Class_Motivation.csv" from the Assignment 4 Repository as a data frame called "K1""
```{r}

K1 <- read.csv(...)
K1 <- read.csv("Class_Motivation.csv",header=T)

```

Expand All @@ -26,7 +28,7 @@ The algorithm will treat each row as a value belonging to a person, so we need t

```{r}

K2 <-
K2 <- select (K1, 2:6)

```

Expand All @@ -47,7 +49,7 @@ Another pre-processing step used in K-means is to standardize the values so that

```{r}

K3 <-
K3 <- scale(K3)

```

Expand All @@ -66,36 +68,52 @@ Also, we need to choose the number of clusters we think are in the data. We will

```{r}

fit <-
fit1a <- kmeans(K3,2)
fit1b <- kmeans(K3,2)
fit1c <- kmeans(K3,2)

#We have created an object called "fit" that contains all the details of our clustering including which observations belong to each cluster.

#We can access the list of clusters by typing "fit$cluster", the top row corresponds to the original order the rows were in. Notice we have deleted some rows.
fit1a$cluster

K4 <-data.frame(K3,fit1a$cluster,fit1b$cluster,fit1c$cluster )

fit1a$withinss
fit1b$withinss
fit1c$withinss

fit1a$tot.withinss
fit1b$tot.withinss
fit1c$tot.withinss

fit1a$betweenss
fit1b$betweenss
fit1c$betweenss


#We can also attach these clusters to the original dataframe by using the "data.frame" command to create a new data frame called K4.

K4
K4 <- data.frame(K3, fit1c$cluster)

#Have a look at the K4 dataframe. Lets change the names of the variables to make it more convenient with the names() command.

names(K4) <- c("1","2","3","4","5","cluster")

```

Now we need to visualize the clusters we have created. To do so we want to play with the structure of our data. What would be most useful would be if we could visualize average motivation by cluster, by week. To do this we will need to convert our data from wide to long format. Remember your old friends tidyr and dplyr!
Now we need o visualize the clusters we have created. To do so we want to play with the structure of our data. What would be most useful would be if we could visualize average motivation by cluster, by week. To do this we will need to convert our data from wide to long format. Remember your old friends tidyr and dplyr!

First lets use tidyr to convert from wide to long format.
```{r}

K5 <- gather(K4, "week", "motivation", 1:5)
K5 <- tidyr::gather(K4, "week", "motivation", 1:5)
```

Now lets use dplyr to average our motivation values by week and by cluster.

```{r}

K6 <- K5 %>% group_by(week, cluster) %>% summarise(K6, avg = mean(motivation))
K6 <- K5 %>% group_by(week, cluster) %>% summarise(avg = mean(motivation))

```

Expand All @@ -113,9 +131,9 @@ Likewise, since "cluster" is not numeric but rather a categorical label we want

```{r}

K6$week <-
K6$week <- as.numeric(K6$week)

K6$cluster <-
K6$cluster <- as.factor(K6$cluster)

```

Expand All @@ -128,32 +146,87 @@ Now we can plot our line plot using the ggplot command, "ggplot()".

```{r}

library(ggplot2)
ggplot(K6, aes(week, avg, colour = cluster)) + geom_line() + xlab("Week") + ylab("Average Motivation")

```

What patterns do you see in the plot?

#Apparently the average motivation of cluster 1 is significantly higher than that of cluster 2 and there is less difference within cluster 1.


It would be useful to determine how many people are in each cluster. We can do this easily with dplyr.

```{r}
K7 <- count(K4, cluster)
K7 <- dplyr::count(K4, cluster)
```

Look at the number of people in each cluster, now repeat this process for 3 rather than 2 clusters. Which cluster grouping do you think is more informative? Write your answer below:

```{r}
fit2 <- kmeans(K3,3)
K4_2<- data.frame(K3, fit2$cluster)
K5_2 <- tidyr::gather(K4_2, "week", "motivation", 1:5)
K6_2 <- K5_2 %>% group_by(week, fit2.cluster) %>% summarise(avg = mean(motivation))
K6_2$week <- as.numeric(K6_2$week)
K6_2$cluster <- as.factor(K6_2$fit2.cluster)
ggplot(K6_2, aes(week, avg, colour = fit2.cluster)) + geom_line() + xlab("Week") + ylab("Average Motivation")

```


##Part II

Using the data collected in the HUDK4050 entrance survey (HUDK4050-cluster.csv) use K-means to cluster the students first according location (lat/long) and then according to their answers to the questions, each student should belong to two clusters.

```{r}
library(tidyverse)
M1 <- read.csv("HUDK405020-cluster.csv", header = T)
M2 <- select(M1, 4:9)
fit2a <- kmeans(M2, 1)
fit2b <- kmeans(M2, 2)
fit2c <- kmeans(M2, 3)
fit2d <- kmeans(M2, 4)
fit2e <- kmeans(M2, 5)
fit2f <- kmeans(M2, 6)
fit2g <- kmeans(M2, 7)

mss <- c(fit2a$tot.withinss,fit2b$tot.withinss,fit2c$tot.withinss,fit2d$tot.withinss,fit2e$tot.withinss,fit2f$tot.withinss,fit2g$tot.withinss,fit2a$betweenss,fit2b$betweenss,fit2c$betweenss,fit2d$betweenss,fit2e$betweenss,fit2f$betweenss,fit2g$betweenss)

clusters <- c(seq(1,7,1),seq(1,7,1))
col <- c(rep("blue",7),rep("red",7))
plot(clusters, mss, col=col)

L1 <- select(M1, 2:3)

plot(L1$long, L1$lat)

fit3a <- kmeans(L1, 2)
fit3b <- kmeans(L1, 2)
fit3c <- kmeans(L1, 2)

fit3a$tot.withinss
fit3b$tot.withinss
fit3c$tot.withinss

ML <- data.frame(M1$compare.features, M1$math.accuracy,M1$planner.use,M1$enjoy.discuss,M1$enjoy.group,M1$meet.deadline,fit2c$cluster,M1$lat,M1$long,fit3a$cluster)

pairs(ML)
```


##Part III

Create a visualization that shows the overlap between the two clusters each student belongs to in Part II. IE - Are there geographical patterns that correspond to the answers?

```{r}
table(ML$fit2c.cluster,ML$fit3a.cluster)
ML2 <- ML %>% group_by(fit2c.cluster,fit3a.cluster)%>%summarise(count = n())
ggplot(ML2, aes(x = fit2c.cluster, y = fit3a.cluster, size = count))+ geom_point()

library(vcd)
P1 <- structable(fit2c$cluster ~ fit3a$cluster)
mosaic(P1, shade = TRUE, legend = TRUE)
```


Expand Down
Loading