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'Solution' #1021
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'Solution' #1021
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Several changes were requested.
app/main.py
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counter = 0 | ||
for i in phrase: | ||
if i.lower() == letter.lower(): | ||
counter += 1 | ||
return counter |
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Do not use single-letter variable names in your code, be more explicit in naming. Besides that, you could implement this task in one line using chaining and built-in string methods.
app/main.py
Outdated
counter = 0 | ||
for char in phrase: | ||
if char.lower() == letter.lower(): | ||
counter += 1 | ||
return counter |
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try to write this code in one line
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This block of code can be expressed more concisely in one line using count
method of str
.
app/main.py
Outdated
counter = 0 | ||
for char in phrase: | ||
if char.lower() == letter.lower(): | ||
counter += 1 | ||
return counter |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
This block of code can be expressed more concisely in one line using count
method of str
.
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Good job!
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