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'Solution' #1021

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'Solution' #1021

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donbas777
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@Dimosphen1 Dimosphen1 left a comment

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Several changes were requested.

app/main.py Outdated
Comment on lines 17 to 21
counter = 0
for i in phrase:
if i.lower() == letter.lower():
counter += 1
return counter

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Do not use single-letter variable names in your code, be more explicit in naming. Besides that, you could implement this task in one line using chaining and built-in string methods.

@donbas777 donbas777 requested a review from Dimosphen1 November 21, 2023 20:43
app/main.py Outdated
Comment on lines 17 to 21
counter = 0
for char in phrase:
if char.lower() == letter.lower():
counter += 1
return counter

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try to write this code in one line

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This block of code can be expressed more concisely in one line using count method of str.

app/main.py Outdated
Comment on lines 17 to 21
counter = 0
for char in phrase:
if char.lower() == letter.lower():
counter += 1
return counter

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This block of code can be expressed more concisely in one line using count method of str.

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@Polyakiv-Andrey Polyakiv-Andrey left a comment

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Good job!

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4 participants