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Initial test code personal repo.
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Srinath Vadlamani committed Apr 25, 2011
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Binary file added codingTests/Mpi_stuff/Sample_mpio
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29 changes: 29 additions & 0 deletions codingTests/Mpi_stuff/Sample_mpio.f90
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!
! The following example demonstrates how to create and close a parallel
! file using MPI-IO calls.
!

PROGRAM MPIOEXAMPLE

USE MPI

IMPLICIT NONE

CHARACTER(LEN=80), PARAMETER :: filename = "/tmp/filef.h5" ! File name
INTEGER :: ierror ! Error flag
INTEGER :: fh ! File handle
INTEGER :: amode ! File access mode

call MPI_INIT(ierror)
amode = MPI_MODE_RDWR + MPI_MODE_CREATE + MPI_MODE_DELETE_ON_CLOSE
call MPI_FILE_OPEN(MPI_COMM_WORLD, filename, amode, MPI_INFO_NULL, fh, ierror)
print *, "Trying to create ", filename
if ( ierror .eq. MPI_SUCCESS ) then
print *, "MPI_FILE_OPEN succeeded"
call MPI_FILE_CLOSE(fh, ierror)
else
print *, "MPI_FILE_OPEN failed"
endif

call MPI_FINALIZE(ierror);
END PROGRAM
Binary file added codingTests/Mpi_stuff/hello1
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37 changes: 37 additions & 0 deletions codingTests/Mpi_stuff/hello1.f90
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program hello_parallel

! Include the MPI library definitons:
include 'mpif.h'

integer numtasks, rank, ierr, rc, len, i
character*(MPI_MAX_PROCESSOR_NAME) name

! Initialize the MPI library:
call MPI_INIT(ierr)
if (ierr .ne. MPI_SUCCESS) then
print *,'Error starting MPI program. Terminating.'
call MPI_ABORT(MPI_COMM_WORLD, rc, ierr)
end if

! Get the number of processors this job is using:
call MPI_COMM_SIZE(MPI_COMM_WORLD, numtasks, ierr)

! Get the rank of the processor this thread is running on. (Each
! processor has a unique rank.)
call MPI_COMM_RANK(MPI_COMM_WORLD, rank, ierr)

! Get the name of this processor (usually the hostname)
call MPI_GET_PROCESSOR_NAME(name, len, ierr)
if (ierr .ne. MPI_SUCCESS) then
print *,'Error getting processor name. Terminating.'
call MPI_ABORT(MPI_COMM_WORLD, rc, ierr)
end if

print "('hello_parallel.f: Number of tasks=',I3,' My rank=',I3,' My name=',A,'')",&
numtasks, rank, trim(name)

! Tell the MPI library to release all resources it is using:
call MPI_FINALIZE(ierr)

end program hello_parallel

19 changes: 19 additions & 0 deletions codingTests/bandf/code/README.txt
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The programs are archived as a self-extracting archive. To extract:

1. Your computer must be in DOS (version 6.22 or earlier) mode. Windows
cannot be running; the programs will not extract while Windows (any
version) is running.

2. At the screen prompts, type:

MD C:\NUMRCL <enter>
CD C:\NUMRCL <enter>
XCOPY [A:] PROGRAMS.EXE <enter> (replace "[A:]" with the
correct floppy drive name, if different)
PROGRAMS.EXE -d <enter>

This will extract all the programs, in the original subdirectories, into
the new directory "NUMRCL". C programs are in the C subdirectory,
FORTRAN in the FOR subdirectory, Mathematica in the MA subdirectory,
Maple in the MWS subdirectory, and Pascal in the PAS subdirectory. The
DTA subdirectory contains data files for all the programs.
169 changes: 169 additions & 0 deletions codingTests/bandf/code/alg021.c
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/*
* BISECTION ALGORITHM 2.1
*
* To find a solution to f(x) = 0 given the continuous function
* f on the interval [a,b], where f(a) and f(b) have
* opposite signs:
*
* INPUT: endpoints a,b; tolerance TOL;
* maximum number of iterations N0.
*
* OUTPUT: approximate solution p or
* a message that the algorithm fails.
*/

#include<stdio.h>
#include<math.h>
#define ZERO 1.0E-20
#define true 1
#define false 0

main()
{
double A,FA,B,FB,C,P,FP,TOL;
int I,NO,OK,FLAG;
FILE *OUP[1];

double absval(double);
double F(double);
void INPUT(int *, double *, double *, double *, double *, double *, int *);
void OUTPUT(FILE **, int *);

INPUT(&OK, &A, &B, &FA, &FB, &TOL, &NO);
if (OK) {
OUTPUT(OUP, &FLAG);
/* STEP 1 */
I = 1;
/* STEP 2 */
OK = true;
while ((I<=NO) && OK) {
/* STEP 3 */
/* compute P(I) */
C = (B - A) / 2.0;
P = A + C;

/* STEP 4 */
FP = F(P);
if (FLAG == 2) fprintf(*OUP,"%3d %15.8e %15.7e \n",I,P,FP);
if ((absval(FP)<ZERO) || (C<TOL)) {
/* procedure completed successfully */
fprintf(*OUP,"\nApproximate solution P = %11.8f \n",P);
fprintf(*OUP,"with F(P) = %12.8f\n",FP);
fprintf(*OUP,"Number of iterations = %3d",I);
fprintf(*OUP," Tolerance = %15.8e\n",TOL);
OK = false;
}
else {
/* STEP 5 */
I++;

/* STEP 6 */
/* compute A(I) and B(I) */
if ((FA*FP) > 0.0) {
A = P; FA = FP;
}
else {
B = P; FB = FP;
}
}
}
if (OK) {
/* STEP 7 */
/* procedure completed unsuccessfully */
fprintf(*OUP,"\nIteration number %3d",NO);
fprintf(*OUP," gave approximation %12.8f\n",P);
fprintf(*OUP,"F(P) = %12.8f not within tolerance : %15.8e\n",FP,TOL);
}
fclose(*OUP);
}
return 0;
}

/* Change function F for a new problem */
double F(double X)
{
double f;

f = ( X + 4.0 ) * X * X - 10.0;
return f;
}

void INPUT(int *OK, double *A, double *B, double *FA, double *FB, double *TOL, int *NO)
{
double X;
char AA;

printf("This is the Bisection Method.\n");
printf("Has the function F been created in the program immediately preceding\n");
printf("the INPUT function?\n");
printf("Enter Y or N\n");
scanf("%c",&AA);
if ((AA == 'Y') || (AA == 'y')) {
*OK = false;
while (!(*OK)) {
printf("Input endpoints A < B separated by blank\n");
scanf("%lf %lf", A, B);
if (*A > *B) {
X = *A; *A = *B; *B = X;
}
if (*A == *B) printf("A cannot equal B\n");
else {
*FA = F(*A);
*FB = F(*B);
if (*FA*(*FB) > 0.0) printf("F(A) and F(B) have same sign\n");
else *OK = true;
}
}
*OK = false;
while(!(*OK)) {
printf("Input tolerance\n");
scanf("%lf", TOL);
if (*TOL <= 0.0) printf("Tolerance must be positive\n");
else *OK = true;
}
*OK = false;
while (!(*OK)) {
printf("Input maximum number of iterations - no decimal point\n");
scanf("%d", NO);
if (*NO <= 0) printf("Must be positive integer\n");
else *OK = true;
}
}
else {
printf("The program will end so that the function F can be created\n");
*OK = false;
}
}

void OUTPUT(FILE **OUP, int *FLAG)
{
char NAME[30];

printf("Select output destination\n");
printf("1. Screen\n");
printf("2. Text file\n");
printf("Enter 1 or 2\n");
scanf("%d", FLAG);
if (*FLAG == 2) {
printf("Input the file name in the form - drive:name.ext\n");
printf("A:OUTPUT.DTA\n");
scanf("%s", NAME);
*OUP = fopen(NAME, "w");
}
else *OUP = stdout;
fprintf(*OUP,"Bisection Method\n");
printf("Select amount of output\n");
printf("1. Answer only\n");
printf("2. All intermeditate approximations\n");
printf("Enter 1 or 2\n");
scanf("%d", FLAG);
if (*FLAG == 2) fprintf(*OUP, " I P F(P)\n");
}


/* Absolute Value Function */
double absval(double val)
{
if (val >= 0) return val;
else return -val;
}
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