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28-xxubin04 #108
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28-xxubin04 #108
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,33 @@ | ||
input = open(0).readline | ||
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tree_num, length = map(int, input().split()) | ||
trees = sorted(list(map(int, input().split()))) | ||
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def binary_search(target, trees): | ||
start = 0 | ||
end = trees[-1] | ||
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while start <= end: | ||
mid = (start + end) // 2 | ||
cutted_trees = 0 | ||
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for i in trees: | ||
if (i - mid) >= 0: | ||
cutted_trees += (i - mid) | ||
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if cutted_trees == target: | ||
return mid | ||
elif cutted_trees > target: | ||
start = mid + 1 | ||
else: | ||
end = mid - 1 | ||
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if cutted_trees >= target: | ||
ans = mid | ||
else: | ||
ans = mid - 1 | ||
Comment on lines
+18
to
+28
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 위 check를 이용한다고 했을 때, ans = 0
lo, hi = 1, max(trees)
while lo <= hi:
mid = (lo + hi) // 2
if check(mid) >= M: # 자르고 남은 나무 길이 합이 원래 가져가고자 했던 길이보다 많거나 같으면
ans = mid # 현재 커팅 지점을 최대 지점으로 저장
lo = mid + 1 # 하한선 증가
else: # 아니라면
hi = mid - 1 # 상한선 감소
print(ans) 이런 식으로 조건을 더 간략하게 할 수 있겠죠? |
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return ans | ||
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print(binary_search(length, trees)) |
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채현이 PR에서도 설명한 부분이긴 한데,
이진 탐색 문제가 어려워질 수록 start, end 값을 조정하기 위한 조건 판별 코드가 길어집니다.
보통 이 부분은 check란 이름의 함수로 따로 분리하는 편입니다.